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The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is

(A)

1

(B)

4

(C)

0.5

(D)

2

NEET - Medical UG-2017 Easy

Answer & Solution:

\(\large{n=2, ~for~Balmer~series~last~wavelength(\lambda_1)\\ {\Large{1\over \lambda_1}}=R[{\Large{1\over 2^2}}-{\Large{1\over \infty^2}}]\\\lambda_1={\Large{4\over R}}\\ n=1, ~for~Lyman~series~last~wavelength(\lambda_2)\\ {\Large{1\over \lambda_2}}=R[{\Large{1\over 1^2}}-{\Large{1\over \infty^2}}]\\\lambda_2={\Large{1\over R}}\\{\Large{\lambda_1\over \lambda_2}}=4 }\)

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Other Questions of the same topic

Q1:

An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude :

(A)

Zero

(B)

\(\large \frac{\mu _{0}n^{2}\: e}{r}\)

(C)

\(\large \frac{\mu _{0}n e}{2r}\)

(D)

\(\large \frac{\mu _{0}n e}{2\pi r}\)

NEET - Medical UG-2015 Medium

Q2:

\(\large \alpha\)-particle consists of :

(A)

2 protons and 2 neutrons only

(B)

2 electrons, 2 protons and 2 neutrons

(C)

2 electrons and 4 protons only

(D)

2 protons only

NEET - Medical UG-2019 Easy

Q3:

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is :

(A)

\(\large \frac{5}{27}\)

(B)

\(\large \frac{4}{9}\)

(C)

\(\large \frac{9}{4}\)

(D)

\(\large \frac{27}{5}\)

NEET - Medical UG-2015 Easy

Q4:

A nucleus of uranium decays at rest into nuclei of thorium and helium. Then :-

(A)

The helium nucleus has less kinetic energy than the thorium nucleus

(B)

The helium has more kinetic energy than the thorium nucleus

(C)

The helium nucleus has less momentum then the thorium nucleus

(D)

The helium nucleus has more momentum then the thorium nucleus

NEET - Medical UG-2015 Medium

Chemistry Biology

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