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The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

(A)

1.389 H

(B)

138.88 H

(C)

0.138 H

(D)

13.89 H

NEET - Medical UG-2018 Medium

Answer & Solution:

\(\large{\text{Current=60mA, Magnetic Potential Energy=25mJ}\\{\Large1\over 2}LI^2=25mJ\\{\Large1\over 2}×L×3600×10^{-6}=25×10^{-3}\\L=13.89H }\)

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NEET - Medical UG-2015 Hard

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