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The half-life of a radioactive substance is 30 minutes. The time (in minutes) taken between 40% decay and 85% decay of the same radioactive substance is :

(A)

60

(B)

15

(C)

30

(D)

45

NEET - Medical UG-2016 Easy

Answer & Solution:

After 40% decay, remaining radioactive substance = 60 %

After 85% decay, remaining radioactive substance = 15 % 

From 60% to 30%, time taken is half life = 30 mins 

From 30% to 15%, time taken is also half life = 30 mins

Total time taken = 30 + 30 = 60 mins 

 

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Other Questions of the same topic

Q1:

The Binding energy per nucleon of \(\large _{3}^{7} \)Li and \(\large _{2}^{4} \)He nucleon are 5.60 MeV and 7.06 MeV, respectively. In the
nuclear reaction the value of energy Q released is:

(A)

19.6 MeV

(B)

-2.4 MeV

(C)

8.4 MeV

(D)

17.3 MeV

NEET - Medical UG-2014 Easy

Q2:

A radio isotope 'X' with a half life 1.4 x 10\(\large ^{9}\) years decays to 'Y' which is stable. A sample of the rock from a cave was found to contain 'X' and 'Y' in the ratio 1 : 7. The age of the rock is :

(A)

1.96 x 10\(\large ^{9}\) years

(B)

3.92 x 10\(\large ^{9}\) years

(C)

4.20 x 10\(\large ^{9}\) years

(D)

8.40 x 10\(\large ^{9}\) years

NEET - Medical UG-2014 Medium

Q3:

Radioactive material 'A' has decay constant '8\(\large \lambda \)' and material 'B' has decay constant '\(\large \lambda \)'. Initially they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that 'A' will be \(\large \frac{1}{e}\: \: ?\)

(A)

\(\large \frac{1}{7\lambda }\)

(B)

\(\large \frac{1}{8\lambda }\)

(C)

\(\large \frac{1}{9\lambda }\)

(D)

\(\large \frac{1}{\lambda }\)

NEET - Medical UG-2017 Easy

Biology Chemistry

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