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In total internal reflection when the angle of incidence is equal to the critical angle for the pair of media in contact, what will be the angle of refraction?

(A)

180°

(B)

0°

(C)

Equal to angle of incidence

(D)

90°

NEET - Medical UG-2019 Medium

Answer & Solution:

\(\large{\text{Given: angle of incidence(i) is equal to the critical angle(C) for the pair of media in contact.}\\i=C\\sin^{-1}\mu=C\\sin~i=\mu sin~r~~~(r=Angle~of ~refraction)\\sin~C=\mu sin~r\\\sin~(sin^{-1}\mu)=\mu sin~r \\sin~r=1\\r=90^o }\)

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Other Questions of the same topic

Q1:

An equiconvex lens has power P. It is cut into two symmetrical halves by a plane containing the principal axis. The power of one part will be :

(A)

0

(B)

\(\Large \frac{P}{2}\)

(C)

\(\Large \frac{P}{4}\)

(D)

P

NEET - Medical UG-2019 Medium

Q2:

In a Young's double slit experiment if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference.

(A)

\(\Large 5 \frac{\lambda}{2} \)

(B)

\(\Large 10 \frac{\lambda}{2} \)

(C)

\(\Large 9 \frac{\lambda}{2} \)

(D)

\(\Large 11 \frac{\lambda}{2} \)

NEET - Medical UG-2019 Easy

Q3:

An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is

(A)

16

(B)

8

(C)

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(D)

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NEET - Medical UG-2016 Medium

Q4:

The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference pattern, the ratio \(\large \frac{I_{max}-I_{min}}{I_{max}+I_{min}}\) will be

(A)

\(\large \frac{2\sqrt{n}}{(n+1)^{2}}\)

(B)

\(\large \frac{\sqrt{n}}{n+1}\)

(C)

\(\large \frac{2\sqrt{n}}{n+1}\)

(D)

\(\large \frac{\sqrt{n}}{(n+1)^{2}}\)

NEET - Medical UG-2016 Medium

Chemistry Biology

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