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An object is placed at a distance of 40 cm from a  concave mirror of focal length 15 cm. If the object is displaced through a distance of 20 cm towards the mirror, the displacement of the image will be

(A)

30 cm towards the mirror

(B)

36 cm away from the mirror

(C)

30 cm away from the mirror

(D)

36 cm towards the mirror

NEET - Medical UG-2018 Medium

Answer & Solution:

\(\large{Mirror formula\\\Large{1\over u}+{1\over v}={1\over f}\\\text{u=object distance from mirror, v=image distance from mirror and f= focal length of mirror}\\\text{Taking initial position of object,}\\\Large{-1\over 40}+{1\over v}={-1\over15}\\\Large{1\over v}={-25\over 600}\\v=-24cm\\\text{Taking new position of Object,}\\\Large{-1\over 15}={1\over v_{new}}+{-1\over 20}\\\Large{1\over v_{new}}={-5\over 300}\\v_{new}=-60cm\\\text{displacement of image=}v_{new}-v=-36cm }\)

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Other Questions of the same topic

Q1:

A beam of light of \(\large \lambda \) = 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between first dark fringes on either side of the central bright fringe is :

(A)

1.2 em

(B)

1.2 mm

(C)

2.4 em

(D)

2.4 mm

NEET - Medical UG-2014 Easy

Q2:

In the Young's double slit experiment the intensity of light at a point on the screen where the path difference is '\(\large \lambda \) is K, ('\(\large \lambda \) being the wave length of light used). The intensity at a point where the path difference is \(\large \lambda \)/4, will be :

(A)

K

(B)

K/4

(C)

K/2

(D)

Zero

NEET - Medical UG-2014 Easy

Q3:

In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away, was found to be 0.2°. What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? (\(\large \mu_{water}\) = 4/3)

(A)

0.266°

(B)

0.15°

(C)

0.05°

(D)

0.1°

NEET - Medical UG-2019 Medium

Q4:

In Young’s double slit experiment the separation d between the slits is 2 mm, the wavelength \(\lambda\) of the light used is 5896 Å and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0·20°. To increase the fringe angular width to 0·21° (with same \(\lambda\)and D) the separation between the slits needs to be changed to

(A)

2.1 mm

(B)

1.9 mm

(C)

1.8 mm

(D)

1.7 mm

NEET - Medical UG-2018 Medium

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