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A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance
points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of emf's is :

(A)

3 : 2

(B)

5 : 1

(C)

5 : 4

(D)

3 : 4

NEET - Medical UG-2016 Medium

Answer & Solution:

Let two emfs be \(E_1 \) and \(E_2\)

So, \(\large \frac{E_1 + E_2}{E_1 - E_2} = \frac{50}{10}\)

On solvinf above equation:

\(\large \frac{E_1}{E_2} = \frac{3}{2}\)

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Other Questions of the same topic

Q1:

The resistance of a wire is ‘R’ ohm. If it is melted and stretched to ‘n’ times its original length, its new resistance will be

(A)

\(\large \frac{R}{n}\)

(B)

\(\large n^{2}R\)

(C)

\(\large \frac{R}{n^{2}}\)

(D)

nR

NEET - Medical UG-2017 Easy

Q2:

A potentiometer is an accurate and versatile device to make electrical measurements of E.M.F, because the method involves :

(A)

Potential gradients

(B)

A condition of no current flow through the galvanometer

(C)

A combination of cells, galvanometer and resistances

(D)

Cells

NEET - Medical UG-2017 Easy

Q3:

A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is \(\large 4\times 10^{-3} \) Wb. The self-inductance of the solenoid is

(A)

1 H

(B)

4 H

(C)

3 H

(D)

2 H

NEET - Medical UG-2016 Medium

Q4:

A capacitor of \(\large 2\mu F\) is charged as shown in the diagram. When the switch S is turned to position 2, the percentage of its stored energy dissipated is :

(A)

80%

(B)

0%

(C)

20%

(D)

75%

NEET - Medical UG-2016 Medium

Chemistry Biology

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