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A filament bulb (500 W, 100 V) is to be used in a 230 V main suply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is :

(A)

\(\large 13 \Omega\)

(B)

\(\large 230\, \Omega\)

(C)

\(\large 46 \, \Omega\)

(D)

\(\large 26 \, \Omega\)

NEET - Medical UG-2016 Medium

Answer & Solution:

\(\Large I = \frac{P}{V} \)

 \(\Large I = \frac{500}{100} \) = 5 A

Net Voltage supply = 230 V 

Potential difference across R is 230 - 100 = 130 V 

\(\Large R = \frac{V}{I} \)

\(\Large R = \frac{130}{5} \) = 26 ohm 

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Other Questions of the same topic

Q1:

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance
points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of emf's is :

(A)

3 : 2

(B)

5 : 1

(C)

5 : 4

(D)

3 : 4

NEET - Medical UG-2016 Medium

Q2:

The metre bridge shown in balanced position with \(\Large \frac{P}{Q} = \frac{I_1}{I_2}\). If we now interchange the positions of galvanometer and cell, will the bridge work ? if yes, what will be balance condition ?

(A)

Yes, \(\Large \frac{P}{Q} = \frac{I_2 - I_1}{I_2 + I_1}\)

(B)

No, no null point

(C)

Yes, \(\Large \frac{P}{Q} = \frac{I_2}{I_1}\)

(D)

Yes,\(\Large \frac{P}{Q} = \frac{ I_1}{I_2}\)

NEET - Medical UG-2019 Medium

Q3:

The charge flowing through a resistance R varies with time t as \(\large Q = at - bt^{2}\), where a and b are positive
constants. The total heat produced in R is :

(A)

\(\large \frac{a^{3}R}{b}\)

(B)

\(\large \frac{a^{3}R}{6b}\)

(C)

\(\large \frac{a^{3}R}{3b}\)

(D)

\(\large \frac{a^{3}R}{2b}\)

NEET - Medical UG-2016 Medium

Chemistry Biology

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